Loop through an array in jQuery

Question

How can I loop through this $user array in jQuery? If 'Failure' returned then error should be printed.

Solution here actually prints it but with this output which is wrong: undefinedadmin_1,admin_2,admin_3

Thanks in advance

<?php
$id = $_POST['id'];

if($id == 1)
{
    $users['data'] = array(array('name'=> 'admin_1'), array('name'=> 'admin_2'), array('name'=> 'admin_2'));
    echo json_encode($users);
}
else
{
    $users['data'] = 'Failure';
    echo json_encode($users);
}
?>



$.ajax({
    type        : 'POST',
    url         : 'list.php',
    data        : 'id=' + text_id,
    dataType    : 'json',
    success     : function(response)
    {
        //IF not 'Failure', loop through the array and print content into div.success
        //IF 'Failure', show div.fail
    }
});

Julian Hollmann · Accepted Answer · 2012-03-06 11:40:00Z

1

if(response.data == 'Failure') {
    console.log('error');
    return false;
}

for(var i = 0; i < response.data.length; i++) {
    if(typeof response.data[i].name != 'undefined') {
        console.log(response.data[i].name);
    }
}

edited Mar 6, 2012 at 11:40

answered Mar 6, 2012 at 10:45

Julian Hollmann

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1 Comment

BentCoder Over a year ago

I have to store names in a variable and print it afterwards but result = result+response.data[i].name + ', '; prints it like this: undefinedadmin_1,admin_2,admin_3

Kris Ivanov · Accepted Answer · 2012-03-06 10:44:07Z

1

if ($.isArray(response)) {
    //loop through array
} else {
    //show error
}

answered Mar 6, 2012 at 10:44

Kris Ivanov

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