Java JSON code throwing an exception

Question

I have this JSON string:

   [{"user_id":"123","email":"[email protected]","lat":"40.748329","lng":"-73.996223",
                    "first_name":"Alex","last_name":"Genadinik"}]

and this Java Code:

            try
            {
                JSONObject obj = new JSONObject(result);

                Log.d( "NAME: " , "test: " + obj.getString("first_name") );       

            }
            catch ( Exception e )
            {
                Log.d( "JSON ERRORZ: " , "some crap happened " + e.getMessage() );  
            }

But it throws this error:

[{"last_name":"Genadinik","first_name":"Alex","lng":"-73.996223","user_id":"1","email":"[email protected]","lat":"40.748329"}] of type org.json.JSONArray cannot be converted to JSONObject

Any idea how I can fix this and simply just extract the values in the JSON?

Thanks!

Kevin · Accepted Answer · 2012-03-07 19:17:28Z

3

The error says it all. You're passing an array an it expects an object.

To fix your error you should remove the square brackets ([, ]) from your JSON string.

An object looks like:

{
    key: 'value'
}

Where as an array looks like:

[
    { key: 'value' },
    1,
    'some string'
]

answered Mar 7, 2012 at 19:17

Kevin

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2 Comments

GeekedOut Over a year ago

But if I use the JSONArray object, whats the function in there that gets me the value? I don't see anything applicable in the API - thanks!

Kevin Over a year ago

You could use the getJSONObject(..) method :).

MByD · Accepted Answer · 2012-03-07 19:17:30Z

2

This JSON string is an array, not object, not the square brackets at the beginning (look here). Use JSONArray instead, and extract the JSONObjects from it.

answered Mar 7, 2012 at 19:17

MByD

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3 Comments

GeekedOut Over a year ago

But if I use the JSONArray object, whats the function in there that gets me the value? I don't see anything applicable in the API - thanks!

GeekedOut Over a year ago

Would it be something like this: JSONArray obj = new JSONArray(result); JSONObject o = obj.getJSONObject(1); Log.d( "NAME: " , "test: " + o.getString("first_name") );

MByD Over a year ago

Yes. but start from index 0 :)]

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