Is there any function for printing a string up to space, e.g.
char* A = "This is a string."
print(A+5);
output: is
I don't want printing character by character.
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Certainly not, you have to write your own functionSunil Kumar B M– Sunil Kumar B M2012-03-09 09:33:32 +00:00Commented Mar 9, 2012 at 9:33
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Malloc a new string the same length as the passed one. Copy char-by-char into the new string until you find a space, then write a \0. printf the new string and then free it.Martin James– Martin James2012-03-09 09:37:34 +00:00Commented Mar 9, 2012 at 9:37
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"I don't want printing character by character." Sorry, all C functions, be they library functions or made by you, print character by character. If you don't want this, you cannot print anything using the C language.Lundin– Lundin2012-03-09 09:38:55 +00:00Commented Mar 9, 2012 at 9:38
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I thought printing a string can be faster than printing each characterDeepak– Deepak2012-03-09 09:41:10 +00:00Commented Mar 9, 2012 at 9:41
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2 Answers
printf("%s", buf) prints the characters from buf until a null terminator is encountered: there is no way to change that behaviour.
A possible solution that does not print character-by-character, does not modify the string to be printed and uses the format specifier %.*s which prints the first N characters from a string:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char* s = "this is a string";
char* space_ptr = strchr(s, ' ');
if (0 != space_ptr)
{
printf("%.*s\n", space_ptr - s, s);
}
else
{
/* No space - print all. */
printf("%s\n", s);
}
return 0;
}
Output:
this
Comments
An istream_iterator tokenizes on whitespace:
#include <sstream>
#include <iostream>
#include <iterator>
int main()
{
const char* f = "this is a string";
std::stringstream s(f);
std::istream_iterator<std::string> beg(s);
std::istream_iterator<std::string> end;
std::advance(beg, 3);
if(beg != end)
std::cout << *beg << std::endl;
else
std::cerr << "too far" << std::endl;
return 0;
}
