How do I get a list of function instances for a python source file?

Question

Let's say I have a file called example.py with the following content:

def func_one(a):
    return 1

def func_two(b):
    return 2

def func_three(b):
    return 3

How would I get a list of function instances for that file? I have tried playing with the compiler,parser and ast modules but I can't really figure it out. It might be a lot easier than that, but it's slightly out of my depth.

EDIT: To be clear I don't want to import the functions.

nah i dont want to import it. i just want access to the function itself. — Glen Robertson
– Glen Robertson, Commented Mar 12, 2012 at 7:29
Without actually importing the module, the problem is much harder (and you'll miss things like import-time actions that populate the module's namespace without using the def keyword, unless you implement your own Python language...). — torek
– torek, Commented Mar 12, 2012 at 7:37

Mikhail Churbanov · Accepted Answer · 2012-03-12 07:29:12Z

4

You can use inspect module:

>>> import inspect
>>> import example
>>> inspect.getmembers(example, inspect.isroutine)
[('func_one', <function func_one at 0x0238CBB0>), ('func_three', <functi
three at 0x0240ADB0>), ('func_two', <function func_two at 0x0240ADF0>)]

answered Mar 12, 2012 at 7:29

Mikhail Churbanov

4,5101 gold badge30 silver badges36 bronze badges

Sign up to request clarification or add additional context in comments.

8 Comments

Glen Robertson Over a year ago

yeah i don't want to import it though.

Glen Robertson Over a year ago

that's close i think. i want to do that without actually importing it

spicavigo Over a year ago

How do you wanna do it then? I mean at least the file will be imported if not the functions. What is your use case?

Glen Robertson Over a year ago

well i guess i could import them, but i don't want the functions to be callable from the interpreter and pollute the local namespace.

spicavigo Over a year ago

local namespace will only have the name of the module you imported. Not the functions which reside in it. The functions need to be qualified with the module name still.

|

Srikar Appalaraju · Accepted Answer · 2012-03-12 07:27:44Z

0

You can use dir. This return the list of names in the current local scope. Although this might return more than function names.

>>> import utils
>>> utils.__name__
'utils'
>>> dir(utils)
['__builtins__', '__doc__', '__file__', '__name__', '__package__', 'human_number', 'islice', 'math', 'prime_factors', 'primes_sieve', 'primes_sieve1', 'proper_divisors', 'pyth_triplet', 'square_of_sum', 'sum_of_nums', 'sum_of_squares', 'test', 'triangle_nums', 'window']

answered Mar 12, 2012 at 7:27

Srikar Appalaraju

74k55 gold badges221 silver badges265 bronze badges

Comments

Denis · Accepted Answer · 2012-03-12 07:32:33Z

0

You could use globals() function, it is return a dict with all global environment where you can find you functions. Example:

d = globals().copy()
l = []
[l.append(k) for k in d if k.startswith('func')]

answered Mar 12, 2012 at 7:32

Denis

7,3919 gold badges41 silver badges59 bronze badges

Comments

fraxel · Accepted Answer · 2012-03-12 07:43:43Z

0

If you really don't want to import into the namespace like this:

import examples
print dir(examples)

['__builtins__', '__doc__', '__file__', '__name__', 
'__package__', 'func_one', 'func_three', 'func_two'] #OUTPUT

You could open and read the file, doing a search for any defs and append those to a list, thus returning all function, and method definition names.

edited Mar 12, 2012 at 7:43

answered Mar 12, 2012 at 7:28

fraxel

35.4k11 gold badges101 silver badges104 bronze badges

Collectives™ on Stack Overflow

How do I get a list of function instances for a python source file?

4 Answers 4

8 Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

8 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related