PHP simple date format

Question

I have a date that I need to convert using PHP date. I've tried a couple different things with no success.

Date coming in: 2011/10/14

Date I need going out: October 2011

Do I need to convert my incoming date to time, and then from time to date going out? I don't understand.

possible duplicate of Convert date/time (PHP) Virtually all questions about converting dates in PHP can be solved by strtotime() or mktime() or the DateTime class. Some more resources: stackoverflow.com/search?q=php+convert+date — No Results Found
– No Results Found, Commented Mar 12, 2012 at 19:30
No need to convert it to time: php.net/manual/en/book.datetime.php — PeeHaa
– PeeHaa, Commented Mar 12, 2012 at 19:31

Gergo Erdosi · Accepted Answer · 2012-03-12 19:31:56Z

6

You can use DateTime and its format() method:

$date = new DateTime('2011/10/14');
echo $date->format('F Y');

answered Mar 12, 2012 at 19:31

Gergo Erdosi

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ThePrimeagen · Accepted Answer · 2012-03-12 19:30:29Z

3

date("F Y", strtotime($date));

answered Mar 12, 2012 at 19:30

ThePrimeagen

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danielrsmith · Accepted Answer · 2012-03-12 19:31:53Z

0

$date_out = date("F Y", strtotime($date_in));

strtotime converts a string value to a timestamp.

date converts a timestamp into a string representation based on the format provided as the first argument.

answered Mar 12, 2012 at 19:31

danielrsmith

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Daniel Ribeiro · Accepted Answer · 2012-03-12 19:32:41Z

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You can almost certainly accomplish that and pretty much almost problem related to date/time convertion using the DateTime class of PHP core.

answered Mar 12, 2012 at 19:32

Daniel Ribeiro

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