How to tackle jSON with javascript

Question

Fist off, here's the jSON object I created with PHPs json_encode function

{
    "Gatwick":[
        {
            "destination":"VCE",
            "destination_name":"Venezia Marco Polo"
        },{
            "destination":"VCE",
            "destination_name":"Venezia Marco Polo"
        },{
            "destination":"VCE",
            "destination_name":"Venezia Marco Polo"
        }
    ],
    "Heathrow":[
        {
            "destination":"VCE",
            "destination_name":"Venezia Marco Polo"
        },{
            "destination":"VCE",
            "destination_name":"Venezia Marco Polo"
        }
    ]
}

Which I think is ok as I understand it. I requested the object using jQuerys $.getJSON(...) function.

Assuming all of that is correct, I can't for the life of me figure out how to access the data in the json object or even illicit any kind of response to indicate anything is happening under the hood.

My latest attempt was to copy the example from the jQuery docs like this...

$.getJSON(url, callBack);

function callBack(data){
    $.each(data.items, function(i, item){
        alert("YO");
    });
}

Which generates the following javascript error

jquery-1.2.6.min.js (line 19) TypeError: Result of expression 'object' [undefined] is not an object.

Which is a little cryptic. Especially since using this

function callBack(data){ alert(data); }

says [object Object]

but this

function callBack(data){ alert(data[0]); }

gives me nothing.

Where am I going wrong here?

Greg · Accepted Answer · 2009-06-09 12:39:49Z

3

The ".items" in the jQuery example is a .NET thing - you have data.Gatwick[0].destination == 'VCE'

answered Jun 9, 2009 at 12:39

Greg

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Comments

Jiaaro · Accepted Answer · 2009-06-09 12:50:55Z

1

you don't have 'items' in your data object... just use

$.each(data, function(i, item){

at which point you can do:

item[0].destination

edited Jun 9, 2009 at 12:50

answered Jun 9, 2009 at 12:35

Jiaaro

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Comments

Daniel A. White · Accepted Answer · 2009-06-09 12:36:28Z

0

The JSON that the PHP is returning is not an array. Notice the curly braces, not square braces.

answered Jun 9, 2009 at 12:36

Daniel A. White

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1 Comment

Jiaaro Over a year ago

that is true.. but I'm pretty sure jquery's $.each will still work, the i variable will just contain the dict key (or whatever javascript calls it, I'm a python guy)

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