Starting a java program from shellscript

Question

I'm complete Linux newbie, but still want to provide a simple way for Linux users to start my Java program. Therefore I want to create a shellscript.

I can't test my script so I'll have to ask here if this is working correctly:

#!/bin/bash
java -cp "bin";"extres/junit.jar" data.ProgramOne
exit 0

This looks good. You don't need the quotes and the "exit 0" line could be removed. If this is something professional and complex, you should test it on linux (use a virtual machine or a ubuntu distribution that you can test without installation) because the launching of the application isn't generally the biggest porting problem. — Denys Séguret
– Denys Séguret, Commented Mar 14, 2012 at 9:32
Question: Why can't you test your script? Why not download some virtualizer like VirtualBox, install Ubuntu and start testing? It's not like in the old days where you needed a separate machine for such testing scenarios... — Thorsten Dittmar
– Thorsten Dittmar, Commented Mar 14, 2012 at 9:32

AlexR · Accepted Answer · 2012-03-14 09:36:45Z

2

Your mistake is in path delimiter. It is ; on Windows and : on Linux. Moreover you should not wrap each classpath fragment with "". On unix you can escape spaces and other forbidden characters using \. So, I'd re-write the java execution line as:

java -cp bin:extres/junit.jar data.ProgramOne

This will run when you are executing script from your app directory where you have subdirectory bin and extres.

answered Mar 14, 2012 at 9:36

AlexR

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digitebs · Accepted Answer · 2012-03-14 09:33:34Z

1

try this:

java -cp "bin:extres/junit.jar" data.ProgramOne

answered Mar 14, 2012 at 9:33

digitebs

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beny23 · Accepted Answer · 2012-03-14 09:34:28Z

1

Java under Unixes uses : as the separator in the classpath, so you'd need (the quotes are not necessary):

#!/bin/bash
java -cp bin:extres/junit.jar data.ProgramOne

answered Mar 14, 2012 at 9:34

beny23

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