Efficient array value replacement

Question

I have an array of values in PHP looking something like this:

$test = array (  
    array( 'val' => 2, 'color' => 'blue' ),  
    array( 'val' => 5, 'color' => 'green' ),  
);

I want to go through all elements of $test and add 1 to all val indices. Now I realize a foreach loop could work, but I am looking for something a little more efficient. The array will potentially have 10's of thousands of elements and hundreds of sub-elements.

I am wondering if there is some type of way that PHP can go through and modify just that index throughout the entire array, based on the argument that I set.

table...columns, so are you working with SQL or PHP arrays here? — user142162
– user142162, Commented Mar 14, 2012 at 18:47
I am working with PHP as I stated in the question. I am simply calling it a table because it is easier to visualize a table with many columns and you are editing a column throughout all data points. A 2d array is essentially just a simplified table — kreynolds
– kreynolds, Commented Mar 14, 2012 at 18:51
You have not told why foreach isn't efficient. Who says that? — hakre
– hakre, Commented Mar 14, 2012 at 18:52
perhaps because it reinvents the wheel. Doing something simple for each collumn of an array can be done with array_walk or array_map. — artragis
– artragis, Commented Mar 14, 2012 at 18:55
I do not think that foreach would be inefficient speed wise, I should have clarified that I want something cleaner programming wise. I may need to do this many times so it is worth it to me to find out if php already has such functionality before I build my own, no point in reinventing what has already been made — kreynolds
– kreynolds, Commented Mar 14, 2012 at 18:55

artragis · Accepted Answer · 2012-03-14 18:47:14Z

1

you can use array_walk and a closure to do it

array_walk($yourArray,function(&$col){$col['val']++});

answered Mar 14, 2012 at 18:47

artragis

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