php if-else failing

Question

What is wrong with this if-else statement.

if((strlen($objectData['pss'] >= 8))AND(strlen($objectData['pss'] <= 20)))
{
  //do my bidding
}
else
{
  echo "String to short or to long";
}

Ultimately I am trying to find if the variable is greater than or equal to 8 chars while being under or equal to 20 chars. My test string is 11 char, and I am seeing string to short/to long. I've done similar to this in the past, so I dunno what I mucked up at the moment (maybe Im just to tired to realize it)

xdazz · Accepted Answer · 2012-03-15 03:02:54Z

2

if (strlen($objectData['pss']) >= 8 && strlen($objectData['pss']) <= 20)

answered Mar 15, 2012 at 3:02

xdazz

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1 Comment

chris Over a year ago

hah. I see what I did wrong between yours and mine.. wow, guess I am just that tired, thank you :-)

Ed Heal · Accepted Answer · 2012-03-15 03:04:16Z

0

if ((strlen($objectData['pss']) >= 8) and (strlen($objectData['pss']) <= 20))
{ 
  //do my bidding 
} 
else 
{ 
  echo "String to short or to long"; 
}

I have corrected you brackets

answered Mar 15, 2012 at 3:04

Ed Heal

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Comments

Andreas Wong · Accepted Answer · 2012-03-15 03:04:23Z

0

Yes you are indeed "to tired".. You are basically counting the length of an expression instead of the string itself:

if((strlen($objectData['pss']) >= 8)AND(strlen($objectData['pss']) <= 20))

answered Mar 15, 2012 at 3:04

Andreas Wong

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