Storing an Array of Strings(const char* stringlist[3])

Question

I have an array of strings that I would like to copy into a struct member for use in the program...

here is what i have as a string array declaration:

const char *stringArray[3] = {"my", "string", "array"};

How can I copy the data into a struct?

You're very vague about what you're trying to do. Do you want pointers to these strings in the struct, so you can access the strings but not modify them? Do you want copies in the struct so you can modify them? Do you need additional memory allocates so the struct can hold larger strings? — David Schwartz
– David Schwartz, Commented Mar 15, 2012 at 5:06
yes, I would like to point to the strings...I don't need to modify them/ — P. Avery
– P. Avery, Commented Mar 15, 2012 at 5:07

Vaughn Cato · Accepted Answer · 2012-03-15 05:11:15Z

2

struct MyStruct {
  std::vector<std::string> strings;
};

MyStruct my_struct;
const char *stringArray[3] = {"my","string","array"};
for (int i=0; i!=3; ++i) {
  my_struct.strings.push_back(stringArray[i]);
}

answered Mar 15, 2012 at 5:11

Vaughn Cato

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Mahesh · Accepted Answer · 2012-03-15 05:06:39Z

1

struct foo {
   std::string fooStr;  // const std::string fooStr;
};

const char *stringArray[3] = {"my", "string", "array"};

foo obj;
obj.fooStr = stringArray[0];

If you don't wish to modify the member variables - then const qualify the member variable and do -

foo obj = { stringArray[0] };

edited Mar 15, 2012 at 5:06

answered Mar 15, 2012 at 4:48

Mahesh

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