Using a different case for a variable name doesn't work

Question

What the heck is wrong with this:

if  ($bb[$id][0] == "bizz")  {
    $BoxType = "bus_box";
} else {
    $Boxtype = "home_box";
}
<div class="<? echo $BoxType; ?>">

$bb[$id][0] can either be 'bizz' or 'home' but no matter what it stops after the first step.

Could you edit that so the code reads correctly? And could you also explain what you have done to test it. — scragar
– scragar, Commented Jun 9, 2009 at 20:05

Tom Haigh · Accepted Answer · 2009-06-09 20:05:36Z

10

PHP variables are case sensitive. The 'T' in $BoxType is lower case in the else block.

answered Jun 9, 2009 at 20:05

Tom Haigh

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Comments

Daniel · Accepted Answer · 2009-06-09 20:09:26Z

5

Not entirely related to your question (which has already been answered), but you may be interested in the ternary operator :)

<div class="<?= $bb[$id][0] == "bizz" ? "bus_box" : "home_box" ?>">

answered Jun 9, 2009 at 20:09

Daniel

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Comments

Cameron · Accepted Answer · 2009-06-09 20:10:14Z

1

Explain what you mean by "it stops after the first step". Tom is correct, $BoxType and $Boxtype are the not same variables, but it sounds like $BoxType is always getting "bus_box". If it were really "stopping after the first step", $BoxType would just be whatever it was initialized to in the event that $bb[$id][0] was "bizz" and $Boxtype would be "home_box".

answered Jun 9, 2009 at 20:10

Cameron

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