os.system (old python) and arguments with parameters

Question

I trying to write simple code that execute os command with parameters

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os

target = "i586"

build = os.system('/usr/bin/hsh --target="target"')

But it always start as /usr/bin/hsh --target=target instead of target=i586. Also subprocess.call not working cause python too old.

Please help me.

'"target"' is a string containing eight characters "target" and not the content of the variable target. — eumiro
– eumiro, Commented Mar 19, 2012 at 10:31

j13r · Accepted Answer · 2012-03-19 10:31:43Z

3

build = os.system('/usr/bin/hsh --target="%s"' % target)

or

build = os.system('/usr/bin/hsh --target="' + target + '"')

answered Mar 19, 2012 at 10:31

j13r

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3 Comments

Alexander Over a year ago

Nice.Thanks.But if i want more than one parameter i must build = os.system('/usr/bin/hsh --target="%s" --mountpoints="%s"' % target, mountpoints) ?

j13r Over a year ago

yes, but put brackets around the args: str % (arg1, arg2, arg3)

avasal Over a year ago

for multiple arguments forming the command first is much simple to understand, cmd = '/usr/bin/hsh --target="%s, %s, %s"' %(target1, target2, target3) then build = os.system(cmd)

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