Passing variable parameters to a method

Question

Hi is there any way for me to pass variable arguments to a method?

public void unMarshalling(String type, int number){

}

So that instead of int, I can make my method such that I am able to pass in float, double, string and other primitive data types(+ string). Any simple examples will be deeply appreciated! Thanks alot!

you mean : variable number of arguments, or generic variable arguments (which can be anything)? — Dr.Kameleon
– Dr.Kameleon, Commented Mar 20, 2012 at 4:09

craftsman · Accepted Answer · 2012-03-20 04:16:13Z

12

Try this:

public void unMarshalling(Object ... params) {

}

Now you can pass any number of arguments of any type:

unMarshalling(23);
unMarshalling("Hello");
unMarshalling("Hello", 45.3);

edited Mar 20, 2012 at 4:16

answered Mar 20, 2012 at 4:09

craftsman

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Comments

Thomas · Accepted Answer · 2012-03-20 04:17:57Z

0

public void unMarshalling(String a, int b){}
public void unMarshalling(String a, float b){}
public void unMarshalling(String a, double b){}
public void unMarshalling(String a, String b){}

It will know which one to call based on the type. If there's really only one function, you can put the 'meat' of it in String/int, then in String/float you can cast the float to an int as you like and call String/int.

public void unMarshalling(String a, float b)
{
  unMarshalling(a,(int)b);
}

answered Mar 20, 2012 at 4:17

Thomas

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Comments

kundan bora · Accepted Answer · 2012-03-20 04:57:10Z

0

Java has var-args functionality, this means you can pass any number of argument in var-args of given type example -

  public void myMethod(int...args)
 {
 }

you can call this as methods as below -

  myMethod(3);

or myMethod(3,4);

or myMethod(3,65,74); and so on.

You can specify any type of argument besides int.

please keep var-args as last argument if you have more then one argument.

answered Mar 20, 2012 at 4:57

kundan bora

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