Parse Error: unexpected T_DOUBLE_ARROW => foreach array assignment

Question

I am trying to create an associative array that collects the following (existing on the db) information using this code:

$pro_xp = array();//array declaration
foreach ($profile_professional_experiences as $each_professional_experience) {
        $pro_xp[] = ('title' => $each_professional_experience->title,
                     'company' => $each_professional_experience->company,
                     'industry' => $eachprofessional_experience->industry,
                     'time_period' => $each_professional_experience->time_period,
                     'duration' => $each_professional_experience->duration);}

This current code wins me a Parse Error message, which is not productive for me. I have seen other assignment questions, but none like this. I'm still new to PHP development, so if this is a rookie mistake, that would be why.

I think if you look again, you will find you forgot the word array... — DaveRandom
– DaveRandom, Commented Mar 20, 2012 at 15:33
I didn't think I needed it since I had declared it above. I thought I was placing those items into the array at that position. BUT, I have to place an array (with those items) into my original array. — Waddler
– Waddler, Commented Mar 20, 2012 at 15:47
You still need the array keyword. You are creating a sub-array, but it is still a new array. $var = ('val', 'val'); is not a valid PHP syntax. — DaveRandom
– DaveRandom, Commented Mar 20, 2012 at 15:49

mgraph · Accepted Answer · 2012-03-20 15:34:24Z

2

foreach ($profile_professional_experiences as $each_professional_experience) {
        $pro_xp[] = array('

answered Mar 20, 2012 at 15:34

mgraph

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1 Comment

Waddler Over a year ago

Thanks. That got me rolling again.

Marc B · Accepted Answer · 2012-03-20 15:40:26Z

0

    $pro_xp[] = array('title' => $each_professional_experience->title,
                ^^^^^---add this

without the array bit, PHP doens't know you want an array. Something like

$x = ("Hello");

is perfectly valid, but isn't defining an array. It's just a string assignment. Unless you're in an array definition context, the => arrow operator isn't valid.

answered Mar 20, 2012 at 15:40

Marc B

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