c++ for loop converted to a while loop

Question

Hi I wrote this code to print out factors of an integer with a for looop

how do i write it with a while loop?

for(int i = 1; i <  integer+1; i++)
{
    if(integer % i == 0)
        cout<< i<<" ";
}

You culd just stop at integer / 2 since numbers that large will obviously not divide evenly into it. How about you try it first and see if you can figure it out? — Ed Swangren
– Ed Swangren, Commented Mar 20, 2012 at 22:22
@KarolyHorvath: ...ok, that's true, but you can always just assume that N is divisible by N. My point is that running the loop on values greater than (n / 2) + 1 is a waste of time. — Ed Swangren
– Ed Swangren, Commented Mar 20, 2012 at 22:31

David Grayson · Accepted Answer · 2012-03-20 22:22:58Z

3

int i = 1;
while (i < integer+1)
{
  if(integer % i == 0)
    cout<< i<<" ";
  i++;
}

Or even better:

int i = 0;
while (++i < integer+1)
{
  if(integer % i == 0)
    cout<< i<<" ";
}

answered Mar 20, 2012 at 22:22

David Grayson

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Comments

Jon · Accepted Answer · 2012-03-20 22:21:52Z

3

int i = 1;
while(i < integer + 1) {
    // your current loop body goes here
    i++;
}

answered Mar 20, 2012 at 22:21

Jon

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Pawan Sharma · Accepted Answer · 2012-09-27 10:09:43Z

0

Following code will print the same result as your for loop in printing.

 int i = 1;
    while(i < integer + 1)
    {
        if(integer % i == 0)
         {   cout<< i<<" "; }
         i++;

    }

answered Sep 27, 2012 at 10:09

Pawan Sharma

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