finding/checking element exists in array [duplicate]

Question

I have an array that contains approx 13 items.

What I'm looking to do, is to find the 10th item in the array and display it.

The output from var_dump is:

array(13) { [0]=> int(0) [1]=> int(1) [2]=> int(2)  etc etc

Ideally, I'd like to check if the 10th element exists first and if it does, display, it.

Many thanks

Do you want the element with index 9 (or 10 if you get the question wrong), or the 10th element of array? An array like so: $arr = Array([1]=>1,[5]=>1,[9]=>1,[10]=>1...) have $arr[9] != to effective 10th element — Luca Rainone
– Luca Rainone, Commented Mar 21, 2012 at 10:23

Sudhir Bastakoti · Accepted Answer · 2012-03-21 10:13:30Z

1


if(array_key_exists(10, $arr)) {
  echo $arr[10];
}

answered Mar 21, 2012 at 10:13

Sudhir Bastakoti

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safarov · Accepted Answer · 2012-03-21 10:11:18Z

1

if(isset($array[9])) echo $array[9];

answered Mar 21, 2012 at 10:11

safarov

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Ascherer · Accepted Answer · 2012-03-21 10:11:59Z

1

echo isset($array[9]) ? $array[9] : null;

that should work

or

if(isset($array[9]))
    echo $array[9];

answered Mar 21, 2012 at 10:11

Ascherer

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Jubin Thomas · Accepted Answer · 2012-03-21 11:10:44Z

1

if(isset($array[9])) { echo $array[9]; }

answered Mar 21, 2012 at 11:10

Jubin Thomas

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Alasdair · Accepted Answer · 2012-03-21 10:11:17Z

0

if (isset($array[9])) echo $array[9];

answered Mar 21, 2012 at 10:11

Alasdair

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