calling method of object of object with call_user_func

Question

consider this simple scenario:

$this->method($arg1, $arg2);

Solution:

call_user_func_array(array($this,'method'), array($arg1, $arg2));

consider this scenario:

$this->object->method($arg1, $arg2);

Should this solution work?

call_user_func_array(array($this->object,'method'), array($arg1, $arg2));

Or should this work?

    call_user_func_array(array($this, 'object','method'), array($arg1, $arg2));

Edit: Will try/catch works for SOAP exception, triger while using call_user_func?

  try {
    $soap_res = call_user_func_array(array($this->service,'getBanana'), array(0, 10));
} catch (SoapFault $fault) {
    die($fault->faultstring)
}

I reckon this is a question/answer site... but the notion of running both solutions to see which one works never occured to you? — Mario
– Mario, Commented Jun 11, 2009 at 13:24
It's a test question sponsored by SO, and you have multiple choices. Answers should be in the form of letters A,B or C. — Jhourlad Estrella
– Jhourlad Estrella, Commented Sep 2, 2013 at 5:19

Greg · Accepted Answer · 2009-06-11 12:07:24Z

76

This should work:

call_user_func_array(array($this->object,'method'), array($arg1, $arg2));

The first argument is a callback type, containing an object reference and a method name.

answered Jun 11, 2009 at 12:07

Greg

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2 Comments

Andy Fleming Over a year ago

To pass the arguments automatically you can use func_get_args(). For example: call_user_func_array(array($this,'method'), func_get_args())

algo Over a year ago

But would that not provoke the first argument (the callback array) to also be passed?

devsnd · Accepted Answer · 2013-12-15 15:58:09Z

8

Here's a hackish variant, might be useful to someone:

$method_name_as_string = 'method_name';
$this->$method_name_as_string($arg1, $arg2);

This uses the PHP variable-variables. Ugly as hell, but not particularly uglier than the others...

edited Dec 15, 2013 at 15:58

answered Aug 1, 2013 at 13:46

devsnd

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