Django - using regex in urls.py to pass values

Question

I just ran into a problem..

I'm trying to build a website at the moment with different pages. So I created a django app called pages, with the following fields:

title
text
URL

The idea is, that users can create new pages and delete existing ones and it actually affects the navigation in real time.

So in my urls.py I wanted to handle this somehow like this:

from django.conf.urls.defaults import *


urlpatterns = patterns('',
  (r'^pages/(/w)', pages.views.display_content),
)

For example there could be a page with URL property "page1", then "page1" should be stored by (/w) and passed over to pages.views.display_content, which then would display the corresponding data. The "page1" page would be accessible through domain.com/pages/page1.

However, as I'm not really good with regex, I think I really need your help. I would be really happy if someone could explain to me how I have to write my URL rule for this..

Good Night :)

Francisco · Accepted Answer · 2012-03-26 17:58:57Z

1

In addition, you could name the parameter that will be captured and passed to your view function with this notation:

...
(r'^pages/(?P<page_name>\w+)', 'pages.views.display_content'),
...

So you can access it with that name in your view function. Its header should look like this:

def display_content(request, page_name):
    ...

edited Mar 26, 2012 at 17:58

answered Mar 26, 2012 at 17:53

Francisco

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