Sorting array into alphabetical order in Python [duplicate]

Question

I have an array called names with a list of 4 names.

e.g

Names[1]='John'

I want to get the program to sort my array so that FOR each item in the array, except the last one, IF the item is bigger than the next one, swap the two items.

I'm ... not sure what you mean by '4 identifiers'. Is what you want not just names.sort()? — Thomas Wouters
– Thomas Wouters, Commented Mar 29, 2012 at 18:06
You need to be more specific. What is example input and desired output. You are wasting our time and your own time if you are so unclear. — dawg
– dawg, Commented Mar 29, 2012 at 19:04

Alex Leach · Accepted Answer · 2012-03-29 18:15:21Z

1

Like this??

names = [ 'Zac' , 'John',  'Andrew' , 'James' ]
for name in sorted(names[:-1]) + [names[-1]]:
    print name
Andrew
John
Zac
James

edited Mar 29, 2012 at 18:15

answered Mar 29, 2012 at 18:07

Alex Leach

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6 Comments

Joe Taylor Over a year ago

This doesn't appear to work? Are you sure "[:-1]" is intentional?

Joe Taylor Over a year ago

I get the error: line 10, in <module> for Name in sorted(Names[:-1]) + Names[-1]: TypeError: unorderable types: str() < int()

Alex Leach Over a year ago

The [:-1] is so that the last item in the list is excluded from the sort operation. We then append the last item onto the sorted list with + names[-1]

Joe Taylor Over a year ago

Python 3, and you've used different bracket types, around both times you've used Names, does that matter?

Alex Leach Over a year ago

In python 3, the use of print was changed so that it's always called as a function. For the above code to work in python3, the print line needs to be changed to have parentheses around name. i.e. print(name)

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