Javascript RegExp : How to detect space character?

Question

I am trying to make a pattern that will return if a string has the following formating:

yyyy / mm / dd ( please note that they are 4 spaces in that string ).

The following code is what I have come with so far, but it still can't detect the space character. Any ideas how to make it work ?

RegExp( /^\d{4}[\s\/\s]\d{2}[\s\/\s]\d{2}$/g ).test( "1234 / 11 / 22" );    
RegExp( /^\d{4}[ \/ ]\d{2}[ \/ ]\d{2}$/g ).test( "1234 / 11 / 22" );

Thanks

Why are you using [] all over the place? I don't see a need for character classes here. — Travis Webb
– Travis Webb, Commented Apr 2, 2012 at 22:25

aefxx · Accepted Answer · 2012-04-02 22:31:45Z

1

regexp = /^\d{4}\s\/\s\d{2}\s\/\s\d{2}$/g;

answered Apr 2, 2012 at 22:24

aefxx

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1 Comment

It is common here to accept an answer if it solved your problem. Please consider accepting.

Ofer Zelig · Accepted Answer · 2012-04-02 22:25:38Z

0

RegExp( /^\d{4}\s\/\s\d{2}\s\/\s\d{2}/g ).test( "1234 / 11 / 22" );

answered Apr 2, 2012 at 22:25

Ofer Zelig

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