troubles creating regex expression

Question

I have a measure device that creates samples in the following format:

V GL020(1)=20110117161703

another example:

V GLXX011(10)=ADEF=*GFSDAS

What I'm trying to do is to create a regex expression that returns GL020 / 1 / 20110117161703 for the first example and GLXX011 / 10 / ADEF=*GFSDAS for the second example.

I found a regex expression that reliably matches the fist two required parts:

.*?(?<Field>(?:[a-z][a-z]*[0-9]+[a-z0-9]*)).*?(?<Count>\d+)

However, i'm still missing the part after the first "=". I don't know if it is important but the part after the first "=" might include characters like "=" itself.

You're having trouble matching everything after the equals-sign? Then match against exactly one equals-sign + everything that follows (which would include more equals-signs of course) — keyser
– keyser, Commented Apr 3, 2012 at 11:18
Couldn't you just skip the first two characters (V ) and replace ( and )= with ` / ` (and if it matters, just their first occurrences)? — Eric
– Eric, Commented Apr 3, 2012 at 11:21

Qtax · Accepted Answer · 2012-04-03 11:19:53Z

4

You could use an expression like:

(\w+)\((\d+)\)=(\S+)

Giving you the substrings that you want in the first, second and third capturing groups.

answered Apr 3, 2012 at 11:19

Qtax

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2 Comments

lightxx Over a year ago

lol. wow. so easy. i spent hours on that one. :((. thank you very much. the third capturing group might include spaces as well. how would i handle that?

Qtax Over a year ago

@lightxx, if you just want to capture everything after the first =, you could change \S+ to .+. (. does not match new lines unless you use the s flag.)

stema · Accepted Answer · 2012-04-03 11:27:49Z

1

Try using this one:

([^\(|\s]+)\((\d+)\)=([\w|\=|\*]+)

edited Apr 3, 2012 at 11:27

stema

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answered Apr 3, 2012 at 11:23

Johnny_D

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1 Comment

stema Over a year ago

@Qtax it was quicker to add here a newline in the answer than to explain in a comment, what should be corrected.

stema · Accepted Answer · 2012-04-03 11:28:19Z

0

please use this regex:

(?<first>\w+)\s(?<second>\w+)(?<third>\(\d+\))=(?<forth>.*)

edited Apr 3, 2012 at 11:28

stema

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answered Apr 3, 2012 at 11:27

Bikee

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