g.:
String string="Marc Louie, Garduque Bautista";
I want to check if a string contains only words, a comma and spaces. i have tried to use regex and the closest I got is this :
String pattern = "[a-zA-Z]+(\\s[a-zA-Z]+)+";
but it doesnt check if there is a comma in there or not. Any suggestion ?
You need to use the pattern
^[A-Za-z, ]++$
For example
public static void main(String[] args) throws IOException {
final String input = "Marc Louie, Garduque Bautista";
final Pattern pattern = Pattern.compile("^[A-Za-z, ]++$");
if (!pattern.matcher(input).matches()) {
throw new IllegalArgumentException("Invalid String");
}
}
EDIT
As per Michael's astute comment the OP might mean a single comma, in which case
^[A-Za-z ]++,[A-Za-z ]++$
Ought to work.
Why not just simply:
"[a-zA-Z\\s,]+"
\s matches more than just spaces.
Use this will best
"(?i)[a-z,\\s]+"
If you mean "some words, any spaces and one single comma, wherever it occurs to be" then my feeling is to suggest this approach:
"^[^,]* *, *[^,]*$"
This means "Start with zero or more characters which are NOT (^) a comma, then you could find zero or more spaces, then a comma, then again zero or more spaces, then finally again zero or more characters which are NOT (^) a comma".
To validate String in java where No special char at beginning and end but may have some special char in between.
String strRGEX = "^[a-zA-Z0-9]+([a-zA-Z0-9-/?:.,\'+_\\s])+([a-zA-Z0-9])$";
String toBeTested= "TesADAD2-3t?S+s/fs:fds'f.324,ffs";
boolean testResult= Pattern.matches(strRGEX, toBeTested);
System.out.println("Test="+testResult);
