PHP if statements with multiple values

Question

Is there a shorter way of writing this?

<? 
if($_GET['id']==1 ||
$_GET['id']==3 ||
$_GET['id']==4 || 
$_GET['id']==5)
{echo 'does it really have to be this explicit?'};
?>

Something like this perhaps?

<?
if($_GET['id']==1 || 3 || 4 || 5){echo 'this is much shorter'};
?>

hsz · Accepted Answer · 2013-10-02 14:30:09Z

32

Just try with:

if ( in_array($_GET['id'], array(1, 3, 4, 5)) ) {}

answered Oct 2, 2013 at 14:30

hsz

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1 Comment

Mike Over a year ago

This is the shortest way I know. Additionally it's much easier to read.

Ricardo · Accepted Answer · 2013-10-02 14:35:44Z

4

Maybe not shorter but more readable. Try the in_array() function:

if (in_array($_GET['id'], array(1, 3, 4, 5)))
{
  echo "What about this?";
}

answered Oct 2, 2013 at 14:35

Ricardo

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Comments

tetri · Accepted Answer · 2013-10-02 14:42:44Z

2

Perhaps switch may help

switch($_GET['id']) {
    case 1: 
    case 3: 
    case 4: 
    case 5:
        echo 'Slect maybe :P';
        break;
}

edited Oct 2, 2013 at 14:42

tetri

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answered Oct 2, 2013 at 14:33

user2672373

1 Comment

djot Over a year ago

I don't know a function select() - can you point me to the manual on php.net? And who votes that up????

Ashoka Mondal · Accepted Answer · 2013-10-02 14:36:43Z

1

You can use regular expression like below:

preg_match(['1-4']);

answered Oct 2, 2013 at 14:36

Ashoka Mondal

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Comments

Sunil Kumar · Accepted Answer · 2013-10-02 14:34:35Z

0

Declare an array:

$values = array(1,3,4,5);

Get your variable

$id = $_GET['id'];

Now use PHP in_array();

if(in_array($id, $values)){
//do something
}

Read about in_array()

answered Oct 2, 2013 at 14:34

Sunil Kumar

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