how can django view access url pattern?

Question

In my urls.py, I direct traffic like this:

url(r'^basic/', 'mysite.views.basicHandler', name='basic'),

Which is handled in my views.py like this:

from django.shortcuts import render_to_response as dr2r

def basicHandler( request ):
    rc = RequestContext(request, {
        "cdn_url" : settings.CDN_BASE_URL,
        "cdn_home" : settings.CDN_SITE_PATH
    })
    return dr2r( 'basic.html', {}, context_instance=rc )

My question is, how can my views handler (basicHandler) access the url pattern (r'^basic/')? Is that inside of the request object?

karthikr · Accepted Answer · 2013-11-27 16:41:11Z

1

Yes, you can get it from the request.META object.

referer = request.META.get('HTTP_REFERER')

Alternatively, you can resolve the URL using reverse() method

from django.core.urlresolvers import reverse

url = reverse('basic')

answered Nov 27, 2013 at 16:41

karthikr

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2 Comments

jedierikb Over a year ago

reverse worked (returned /basic/), but the HTTP_REFERER did not (returned None) ... any ideas what might cause that?

Peter DeGlopper Over a year ago

HTTP_REFERER, if present in the request at all, would be the URL of the previous page, not the current page. request.path and request.path_info are where I'd start. request.resolver_match might also be useful, depending on exactly what you want to do.

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