Is this possible in C or C++? I have a function with the following declaration:
int foo(double*)
And I am trying to do something like this:
foo([] = {1.0, 2.0, 3.0, 4.0});
I know that I can create an array separately, but I am curious if I can do it that way.
Thanks.
In C: use C99 compound literals:
foo((double[]){ 1.0, 2.0, 3.0, 4.0 });
In C++: (I hate "C/C++" questions!) - I tried this and used C++11 initializer lists in a similar way. However, I'm not entirely confident whether this is legal or results in undefined behavior:
foo(&(std::vector<double> { 1, 2, 3, 4 })[0])
Anyone could confirm this? (compiles with no warnings, runs... that doesn't mean anything, though.)
Yes you can do that by compound literals. C99 allows this feature.
foo((double[]){1.0, 2.0, 3.0, 4.0});
In this example, the compound literal creates an array (on the fly) containing the four floats.
You may also write this
foo((double[4]){1.0, 2.0, 3.0, 4.0});
syntax error : '=', using VS 2012.