undefined variable error in foreach loop

Question

I have a problem where I use this foreach code. I receive an undefined variable: task error.

<?
  $data = file_get_contents('data.json');
  $array = json_decode($data, 1);
  foreach ($array as $task) { ?>
    <tr>
      <td>
        <?= $task['name'] ?>
      </td>
      <td>Data</td>
      <td>Data</td>
      <td>Data</td>
      <td><button class="btn btn-primary"><?= icon('stop'); ?></button></td>
      <td><button class="btn btn-danger"><?= icon('times'); ?></button></td>
    </tr>
  <? } 
?>

use the classical arsenal to see what happens, ini_set('display_errors', 'On'), var_dump, print_r, json_last_error. — Casimir et Hippolyte
– Casimir et Hippolyte, Commented Feb 20, 2017 at 12:05
I suspect you don't have short_tags enabled in your php.ini. — Barmar
– Barmar, Commented Feb 20, 2017 at 12:10

Asfandyar Khan · Accepted Answer · 2017-02-20 12:09:25Z

1

You forget to add the start of php file <?php and at the end <?php } ?>, which will result in different errors

<?php
$data = file_get_contents('data.json');
$array = json_decode($data , 1);
foreach ($array as $task) { ?>
    <tr>
        <td>
            <?= $task['name']; ?>
        </td>
        <td>Data</td>
        <td>Data</td>
        <td>Data</td>
        <td><button class="btn btn-primary"><?= icon('stop'); ?></button></td>
        <td><button class="btn btn-danger"><?= icon('times'); ?></button></td>
    </tr>
<?php }
?>

edited Feb 20, 2017 at 12:09

answered Feb 20, 2017 at 11:59

Asfandyar Khan

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1 Comment

Barmar Over a year ago

Why should he try this? The answer should explain what was wrong in the original code and how you fixed it.

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