I have an array of numbers newArr, whose length I use to create an array filled with zeros zeroArr
const newArr = [1,3,5,8,9,3,7,13]
const zeroArr = Array.from(Array(newArr.length), () => 0);
console.log(zeroArr) // [0,0,0,0,0,0,0,0]
Now, I need to replace the last index value 0 to 10 so it should look like this:
const result = [0,0,0,0,0,0,0,10]
How to do this?
You can replace the last item in the array like this:
result[result.length-1] = 10;
const newArr = [1,3,5,8,9,3,7,13];
const zeroArr = Array.from(Array(newArr.length), () => 0);
let result = zeroArr.slice(); // To create a copy
result[result.length-1] = 10;
console.log(result);
Array.fill()? var zerroArr = newArr.fill(0); zerroArr[zerroArr.length-1]=10; will be executed faster.You could use Array#map and check if the last element, then return 10 otherwise zero.
var array = [1, 3, 5, 8, 9, 3, 7, 13],
copy = array.map((_, i, a) => 10 * (i + 1 === a.length));
console.log(copy);another option could be:
const newArr = [1,3,5,8,9,3,7,13]
const zeroArr = newArr.map(()=>0);
const arrWith10 = [...zeroArr.slice(0,-1), 10]
console.log(zeroArr) // [0,0,0,0,0,0,0,0]
console.log(arrWith10) // [0,0,0,0,0,0,0,10]You have to copy the values in the newArr to zeroArr first then push the value 10 to the index you wanted in ZeroArr. And Print to values in 'ZeroArr'
zeroArr[zeroArr.length-1] = 10. I would suggest you to read basics of programming.10, but i need to replace the last index in my zeroArr arrayresult = [0,0,0,0,0,0,0,10]like this.