Store regex pattern in a variable in bash script

Question

I have the following bash script code:

GOAL="${1:-help}"
TARGET="${2}"
MODULES_LIST="app|tester"

echo "-> Running $TARGET..."
MODULES_LIST_PATTERN = "^($MODULES_LIST)$"
if [[ "$TARGET" =~ $MODULES_LIST_PATTERN ]]; then
    run_${TARGET}
else
    print_error "You must include an existing module: {$MODULES_LIST}"
    exit 1
fi

As you can see, I have a MODULES_LIST variable where I store the modules supported by the application, then I create a regex pattern MODULES_LIST_PATTERN containing the value of the previous var, and use it to check if the provided parameter matches any of the modules. However, it is not working as expected, since when I run ./myscript.sh run app it prints ERROR] You must include an existing module: {app|tester}.

Could someone tell me the proper way of doing this?

beni0888 · Accepted Answer · 2019-01-10 20:48:36Z

2

My fault... the problem is MODULES_LIST_PATTERN = "^($MODULES_LIST)$", you can't have whitespaces surrounding the equals sign. After fixing that, it works as expected.

answered Jan 10, 2019 at 20:48

beni0888

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Torrino Over a year ago

Appreciate you coming back to this and answering it immensely!

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