Bash: split list of files into different files?

Question

I have several files in a directory like:

data1.dat
data2.dat
....
data24678.dat

To run another code, I need to have a text file with the names of the files but I need to split in 50 files per text file, like: File1.txt :

/PATH/OF/FILE/data1.data
/PATH/OF/FILE/data2.data
/PATH/OF/FILE/data3.data
......
/PATH/OF/FILE/data50.data

File2.txt :

/PATH/OF/FILE/data51.data
/PATH/OF/FILE/data52.data
/PATH/OF/FILE/data53.data
......
/PATH/OF/FILE/data100.data

any idea?? I was trying like:

ls -1 | xargs -n 50 >> File1.txt

but I don't know who to select each "item" in the xargs command. Thanks!!

Hauke Laging · Accepted Answer · 2014-04-04 23:10:52Z

3

ls -1 | split --lines=10

puts the files in the same directory. This can be avoided by

ls -1 | (cd /where/ever; split --lines=10)

or for a different file name:

ls -1 | split --lines=10 /dev/stdin /path/to/splitfile.

answered Apr 4, 2014 at 22:32

Hauke Laging

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Graeme · Accepted Answer · 2014-04-04 22:48:00Z

1

Try this (uses GNU split which is default on most Linux distros):

ls |
  sed "s:^:$(pwd)/:" |
  split -dl 50 --additional-suffix=.txt - /path/to/dest/File

answered Apr 4, 2014 at 22:48

Graeme

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2 Answers 2