Initializing instance variable for use outside of the method

Question

I have a variable called "amount" in one of my methods but I need to make reference to it in another method. I'm not sure of the syntax used.

Here is the code:

public static void startup()
{
    String message = "Welcome to Toronto Mutual!";
    //prompts user to enter their employee ID
    String logIn = JOptionPane.showInputDialog("Please enter your employee `enter code here`ID.");
    int employeeID = Integer.parseInt(logIn);

    String input = JOptionPane.showInputDialog("Please enter the transaction `enter code here`type, bank ID and amount all separated by a comma.");
    input=input.toUpperCase();
    if (input.equals("END")){
        JOptionPane.showMessageDialog(null,"Goodbye.");
        System.exit(0);
    }
    else
    {
        int balance = 100;
        String []transaction = new String[3];
        transaction = input.split(",");
        String type = transaction[0]; 
        int bankID = Integer.parseInt(transaction[1]);
        type=type.toUpperCase();
... // there's more but it's irrelevant

How do I use the variable "amount" and "bankID" outside of the method?

Don't see both "amount" and "bankID" in the code. But if you really need to reference it in another method, just initialize it outside this startup() method. private string amount; and do whatever you want with it in this method. You can read it from another method -- just make sure you're calling it in the correct order. — Ann B. G.
– Ann B. G., Commented Apr 5, 2012 at 0:47

Mingyu · Accepted Answer · 2013-06-02 16:56:19Z

1

Two ways:

Pass amount to the other method through argument

private void otherMethod(int amount) {...}
Create an instance variable so that you can access it within the class scope

private int amount;

If you go with this route, it is better to use getter and setter.
```
public int getAmount() {
    return amount;
}

public void setAmount(int amount) {
    this.amount = amount;
}
```

answered Jun 2, 2013 at 16:56

Mingyu

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