Remove value from array based on value?

Question

I have a PHP array with a parent called "items." In that array, I want to remove all values that do not contain a string (which I'm gonna use regex to find). How would I do this?

if you're just looking to match against a string, consider using strpos instead of a RegEx - faster, especially if the Array is large. — Madbreaks
– Madbreaks, Commented Apr 26, 2012 at 17:22

Nadh · Accepted Answer · 2012-04-26 17:19:46Z

4

foreach($array['items'] as $key=>$value) { // loop through the array
    if( !preg_match("/your_regex/", $value) ) {
        unset($array['items'][$key]);
    }
}

answered Apr 26, 2012 at 17:19

Nadh

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Comments

gen_Eric · Accepted Answer · 2012-04-26 17:30:36Z

2

You can try using array_filter.

$items = array(
    #some values
);
$regex= '/^[some]+(regex)*$/i';
$items = array_filter($items, function($a) use ($regex){
    return preg_match($regex, $a) !== 0;
});

NOTE: This only works in PHP 5.3+. In 5.2, you can do it this way:

function checkStr($a){
    $regex= '/^[some]+(regex)*$/i';
    return preg_match($regex, $a) !== 0;
}

$items = array(
    #some values
);
$items = array_filter($items, 'checkStr');

edited Apr 26, 2012 at 17:30

answered Apr 26, 2012 at 17:16

gen_Eric

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1 Comment

Madbreaks Over a year ago

I prefer this approach to brute force looping over the array, good answer.

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