Remove array element by checking a value php

Question

I have an array as follows

[0=>['classId'=>2,'Name'=>'John'],1=>['classId'=>3,'Name'=>'Doe'],2=>['classId'=>4,'Name'=>'Stayne']]

I need to remove the elements with classId 2 or 4 from array and the expected result should be

[0=>['classId'=>3,'Name'=>'Doe']]

How will i achieve this without using a loop.Hope someone can help

You can't do it without a loop. If you mean how to do it with built-in PHP functions, that's a different thing. But even those will internally loop. — El_Vanja
– El_Vanja, Commented Mar 18, 2021 at 14:37
@El_Vanja I can use array functions in php.I know it still use loops — Vimal
– Vimal, Commented Mar 18, 2021 at 14:38

Steven · Accepted Answer · 2021-03-18 15:03:50Z

1

You can use array_filter in conjunction with in_array.

$array = [0=>['classId'=>2,'Name'=>'John'],1=>['classId'=>3,'Name'=>'Doe'],2=>['classId'=>4,'Name'=>'Stayne']];

var_dump(

    array_filter($array, function($item){return !in_array($item["classId"], [2,4]);})

);

Explanation

array_filter

Removes elements from the array if the call-back function returns false.

in_array

Searches an array for a value; returns boolean true/false if the value is (not)found.

answered Mar 18, 2021 at 15:03

Steven

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Comments

bartholomew · Accepted Answer · 2021-03-18 14:47:31Z

0

Try this:

foreach array as $k => $v{
    if ($v['classId'] == 2){
        unset(array[$k]);
    }
}

I just saw your edit, you could use array_filter like so:

function class_filter($arr){
    return ($arr['classId'] == "whatever");
}
array_filter($arr, "class_filter");

Note: you'll still need to loop through a multi-dimensional array I believe.

edited Mar 18, 2021 at 14:47

answered Mar 18, 2021 at 14:37

bartholomew

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