I am trying to drop tables, which have a particular suffix(passed as argument $1), using shell script.
If a parent table is selected without its child tables being dropped, I am bypassing the parent table and increasing the counter in the exception block.
When I run this script in sql developer with $1 replaced with the proper value, it works. But when I run this shell script, it is getting stuck.
Could you please have a look and let me know, what am I missing in the shell script?
Code:
#!/bin/bash
cat <<ENDDROPNEWTABS >dropnewtabs.sql
set pagesize 100
DECLARE
t_cnt NUMBER;
CURSOR C001
IS
SELECT table_name FROM user_tables WHERE table_name LIKE '%$1%';
BEGIN
BEGIN SELECT COUNT(*) INTO t_cnt FROM user_tables WHERE table_name LIKE '%$1%';
END;
WHILE(t_cnt > 0) LOOP
FOR i IN C001 LOOP
BEGIN EXECUTE IMMEDIATE 'DROP TABLE '||i.table_name;
EXCEPTION
WHEN OTHERS THEN
t_cnt := t_cnt+1;
NULL;
END;
t_cnt := t_cnt-1;
END LOOP;
END LOOP;
END;
exit
ENDDROPNEWTABS
echo "Dropping the tables created for this task..."
sqlplus -s usn/pwd@sid @dropnewtabs.sql >tablesDropped.txt
#END