PHP form Loop Variables

Question

I am working on a PHP form that allows a user to add rows to a table and then submit the information using the form through email. I need to pass the variables into the email. I have tried using this:

$n = count($type);
$i = 0;
for ($i = 0; $i < $n; $i++){
    $e_classes = "______________________________________________ \r\n\n";
    $e_classes .=  "Class Type: {$type[$i]} \r\n";
    $e_classes .= "Number of Classes: {$nc[$i]} \r\n";
    $e_classes .= "Number of Students: {$sc[$i]} \r\n";
    $e_classes .= "______________________________________________ \r\n\n";
}

But when I get the email only the last one in the table is displaying. How would I get all of the added table rows to display? I can make everything work if I use 'echo', but I need to pass everything into a variable that I can use for an email.

Change the first instance of $e_classes = " to $e_classes .= " — Josh
– Josh, Commented Jun 27, 2012 at 16:14
Every time you enter that for loop you override your $e_classes variable — Alvaro Arregui
– Alvaro Arregui, Commented Jun 27, 2012 at 16:15

David Bélanger · Accepted Answer · 2012-06-27 16:20:09Z

6

Like this :

$e_classes = '';
$n = count($type);
$i = 0;
for ($i = 0; $i < $n; $i++){
    $e_classes .= "______________________________________________ \r\n\n";
    $e_classes .=  "Class Type: {$type[$i]} \r\n";
    $e_classes .= "Number of Classes: {$nc[$i]} \r\n";
    $e_classes .= "Number of Students: {$sc[$i]} \r\n";
    $e_classes .= "______________________________________________ \r\n\n";
}

Your first entry in your loop for the variable $e_classes was erasing what she had before because you used $e_classes = instead of $e_classes .=.

This mean before each loop, your variable was reset with the value of your first row.

You were doing this :

$Var = '';
for($i = 0, $i < n; $i++){
    $Var = 'a';
}

// Loop 1
$Var = 'a';

// Loop 2
$Var = 'a';

// Loop 3
$Var = 'a';

You wanted this :

$Var = '';
for($i = 0, $i < n; $i++){
    $Var .= 'a';
}

// Loop 1
$Var = 'a';

// Loop 2
$Var = 'aa';

// Loop 3
$Var = 'aaa';

The symbol = will overwrite the variable's value with the new one.

The symbol .= will append the value at the end of the variable.

edited Jun 27, 2012 at 16:20

answered Jun 27, 2012 at 16:14

David Bélanger

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2 Comments

blutick Over a year ago

FREAKIN BRILLIANT! Thanks so much for the help, worked perfectly!!

David Bélanger Over a year ago

@blutick Your welcome. Just mark as answered the question please. Thanks.

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