Android development Array comparing with int

Question

Beginner in Android development. My code crashes. I have made a simple Java method like a inArray function in php.

private ArrayList<Long> inArray(int array[], int searched)
{
    ArrayList<Long> ans = new ArrayList<Long>();

    for(int i = 0; i <= array.length; i++)
    {
          if (array[i] == searched)
          {
              ans.add((long) i);
          }
    } 

    return ans;
}

It doesn't work on this stage

if (array[i] == searched)

How can i Compare them ? I have tried many things but the code just keeps crashing. Thank you very much.

Cant believe that this little peace of .... was the problem. Interesting why ? Will look in to it. Thank you very much. — Rasim Mehtijev
– Rasim Mehtijev, Commented Jun 27, 2012 at 20:43
array.length returns the number of elements. In a 10 element array, it returns 10, while the elements are 0-9. When it gets to 10, it crashes with an arrayOutOfBounds exception. — Geobits
– Geobits, Commented Jun 27, 2012 at 20:50
your problem get solved or not? problem is because you are using i=0 and looping to length-1 — ρяσѕρєя K
– ρяσѕρєя K, Commented Jun 27, 2012 at 20:55

ρяσѕρєя K · Accepted Answer · 2012-06-27 21:06:17Z

4

use

for(int i = 0; i <array.length; i++)

or

for(int i = 0; i <= array.length-1; i++)

instead of

for(int i = 0; i <= array.length; i++)

answered Jun 27, 2012 at 21:06

ρяσѕρєя K

133k54 gold badges203 silver badges216 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Android development Array comparing with int

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related