How to compare Integer with integer array

Question

i am new to android. I want to know how to compare Integer with integer array. There is a set of integer array (Ex) array_int={1,2,3,4} and single integer int i=2, here i want to compare both integers,and in case if single integer appears in array integer, i want to break the process.

for(i=0;i<integerArray.length;i++){
    if(singleinteger!=integerArray[i]){ // some action       }
else{
// Stop the action  }

In this case it compares both integer. and at the time when two integers are equal process getting break, otherwise it iteration action till the loop getting end.

paxdiablo · Accepted Answer · 2011-03-11 09:39:08Z

3

For a simple solution, use:

for (i = 0; i < intArray.length; i++) {
    if (singleInt != intArray[i]) {
        // some action
    } else {
        break;
    }
}

That will break from the loop when the two values are equal. However, some purists don't like the use of break since it can introduce readability issues, especially if your some action is large (in terms of lines of code) since that removes an exit condition far away from the for itself.

To fix that, you may want to consider reversing the sense of the if statement so that that exit condition is closer to the for:

for (i = 0; i < intArray.length; i++) {
    if (singleInt == intArray[i])
        break;

    // some action
}

and that will also let you remove the else (that's the else itself, not its contents) since it's not needed any more.

But, if you're going to do that, you may as well incorporate it totally into the for and be done with it:

for (i = 0; (i < intArray.length) && (singleInt != intArray[i]); i++) {
    // some action
}

edited Mar 11, 2011 at 9:39

answered Mar 11, 2011 at 5:29

paxdiablo

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1 Comment

RAAAAM Over a year ago

Yeah, i am trying out your solution, thanks for your comment.

Reno · Accepted Answer · 2011-03-11 05:28:28Z

2

Use a

break;

inside your loop.

edited Mar 11, 2011 at 5:28

answered Mar 11, 2011 at 5:11

Reno

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3 Comments

Mahesh Over a year ago

It's not inside the loop. It's inside the else statement.

Jigar Joshi Over a year ago

@HariRam to stop the action use break;

Ted Hopp Over a year ago

@Mahesh the if-else statement is inside the for loop. A break inside the else will terminate the loop.

Corey Sunwold · Accepted Answer · 2011-03-11 05:20:35Z

1

for(i = 0; i < integerArray.length; i++ {
    if(singleinteger != integerArray[i] { 
        //some action
    }
    else { 
        break; //add this line
    }
}

answered Mar 11, 2011 at 5:20

Corey Sunwold

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Comments

BenMorel · Accepted Answer · 2014-06-17 09:10:29Z

1

If you want you can read up on Integer test here

Otherwise in your code your simply missing the "exit" of your loop.

    for(i=0;i<integerArray.length;i++){
        if(singleinteger!=integerArray[i]){ // some action
    }else{
    // Stop the action  
       break;
    }

but that is only if you don't need to process the rest of your array.

edited Jun 17, 2014 at 9:10

BenMorel

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answered Mar 11, 2011 at 5:31

Jason Rogers

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