Trouble with a small php function Http Error 500

Question

I'm just learning php, To practice i want to try and make a php function that can generate CSS3 gradients easily in a document.

I am running into HTTP Error 500. here's the code :

<?php
function cgrad($c1,$c2,$applyto)
{
echo 
"<style type="text/css">
$applyto {
background-image: -ms-linear-gradient(top, $c1 0%, $c2 100%);
background-image: -moz-linear-gradient(top, $c1 0%, $c2 100%);
background-image: -o-linear-gradient(top, $c1 0%, $c2 100%); 
background-image: -webkit-gradient(linear, left top, left bottom, color-stop(0, $c1), color-stop(1, $c2));
background-image: -webkit-linear-gradient(top, $c1 0%, $c2 100%);
background-image: linear-gradient(to bottom, $c1 0%, $c2 100%);
height : 100%;
width : 100%;}
</style>";
};
?>
<html>
<head>
<?php
cgrad(#FFFFFF,#000000,body);
?>
</head>
<body>
testing
</body>
</html>

Any help is much appreciated.

HTTP 500 can occur when there are syntax errors in PHP. For future refernce, always check your code for ending semicolons, proper quotes, and things of that nature. — honyovk
– honyovk, Commented Jul 5, 2012 at 16:37
Thanks very much to both people who responded, Sorry about it being such a simple problem, Being new to php i didn't notice it. Many thanks — jmaris
– jmaris, Commented Jul 5, 2012 at 16:46

gen_Eric · Accepted Answer · 2012-07-05 16:35:54Z

5

echo 
"<style type="text/css">

You can't put double quotes inside double quotes. You can either escape them (like the other answers say) or use single quotes.

echo 
"<style type='text/css'>

Also, you need quotes when calling cgrad.

<?php
cgrad('#FFFFFF','#000000','body');
?>

answered Jul 5, 2012 at 16:35

gen_Eric

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1 Comment

honyovk Over a year ago

The cgrad function's parameters need to be quoted because the pound # creates a comment.

andrewsi · Accepted Answer · 2012-07-05 16:34:01Z

2

echo 
"<style type="text/css">

You're using quotes both to delimit your echo statement, and inside it - PHP can't figure out what quotes are which. One way is to escape the quotes inside the echo statement:

echo 
"<style type=\"text/css\">

answered Jul 5, 2012 at 16:34

andrewsi

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