Python: Concatenate URL and Integer

Question

I am trying to concatenate url and integer base on the iteration of the loop. But I am getting error: TypeError: not all arguments converted during string formatting

for i in range(0,20):
    convertedI = str(i)
    address = 'http://www.google.com/search?q=%s&num=100&hl=en&start='.join(convertedI) % (urllib.quote_plus(query))

I also tried to urllib.urlencode function but ended up getting the same error.

I guess I should have mentioned in addition to query which is a string that I pass it in in my main I want assign current iteration value to the start parameter in the url > &start=1

so first iteration I would like to have my url as

http://www.google.com/search?q=%s&num=100&hl=en&start=1' % (urllib.quote_plus(query))

Daniel DiPaolo · Accepted Answer · 2012-07-17 18:58:28Z

3

for i in range(0, 20):
    address = 'http://www.google.com/search?q=%s&num=100&hl=en&start=%s' % (urllib.quote_plus(query), i)

No need to use str as %s implicitly does that for you. Nor is there a need to join, as join is used to take multiple strings within a sequence and pull them together with a join character. You just want simple string formatting.

edited Jul 17, 2012 at 18:58

answered Jul 17, 2012 at 18:52

Daniel DiPaolo

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3 Comments

David Robinson Over a year ago

This doesn't use i anywhere in the URL, which the question clearly intended to.

Daniel DiPaolo Over a year ago

@DavidRobinson yup, the original construction confused me, I assume he means to concatenate i to the end so I've updated my answer

add-semi-colons Over a year ago

I have edited the question to be more clear. Sorry for any confusion.

BrenBarn · Accepted Answer · 2012-07-17 18:52:38Z

1

I think you are misunderstanding what join does. It uses its argument as a delimiter to join the elements of a passed sequence:

>>> ','.join(['a', 'b', 'c'])
'a,b,c'

It sounds like you just want to do "http://..." + convertedI, but it's not clear exactly what you're trying to do. Where do you want convertedI and the urllib.quote_plus(query) value to go in the string?

answered Jul 17, 2012 at 18:52

BrenBarn

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2 Comments

add-semi-colons Over a year ago

I tried this but I am getting TypeError: not all arguments converted during string formatting address = 'google.com/search?q=%s&num=100&hl=en&start=' + convertedI % (urllib.quote_plus(query))

David Robinson Over a year ago

Why did you put a semicolon in there? As you have it, you'd have to put parentheses around the url and convertedl (order of operations would otherwise try and add the query to the convertedl string). Daniel DiPaulo's answer is best, though.

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