JavaScript/RegExp replace portion of string

Question

I have a string something like:

foo title:2012-01-01 bar

Where I need to get the 'title:2012-01-01' and replace the date part '2012-01-01' to a special format. I just am not good at RegExp and currently have:

'foo from:2012-01-01 bar'.replace(/from:([a-z0-9-]+)/i, function() {
    console.log(arguments);
    return 'replaced';
})

and that returns

foo replaced bar

which is a start but not exactly correct. I need the 'from:' not to be replaced, just the '2012-01-01' be replaced. Tried using (?:from:) but that didn't stop it from replacing 'from:'. Also, I need to take into account that there may be a space between 'from:' and '2012-01-01' so it needs to match this also:

foo title: 2012-01-01 bar

Somewhat confused: is 'title' a keyword? What about 'from'? Or are you looking for any word followed by a colon? Giving us at least one example of both expected inputs and outputs would be tremendously helpful here. — Godwin
– Godwin, Commented Jul 31, 2012 at 20:28
Also, is logging the arguments a requirement or is this just debug code? — Godwin
– Godwin, Commented Jul 31, 2012 at 20:31
'title' was a typo on my part, should have been 'from'. The console.log(arguments) is just debug code, will be doing some date calc later. — Mitchell Simoens
– Mitchell Simoens, Commented Jul 31, 2012 at 21:29

Daedalus · Accepted Answer · 2012-07-31 20:57:56Z

3

The following should do what you need it to; tested it myself:

'foo from:2012-01-01 bar'.replace(/(\w+:\s?)([a-z0-9-]+)/i, function(match, $1) {
    console.log(arguments);
    return $1 + 'replaced';
});

DEMO

It will match both title: etc and from:etc. The $1 is the first matched group, the (\w+:\s?), the \w matches any word character, while the \s? matches for at least one or no spaces.

answered Jul 31, 2012 at 20:57

Daedalus

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1 Comment

Godwin Over a year ago

If you're looking for at least one space (possibly more) I would suggest replacing the \s? with \s* (zero or more space characters).

Godwin · Accepted Answer · 2012-07-31 21:36:55Z

0

If the format is always from:... there should be no need to capture the 'from' text at all:

'foo from:2012-01-01 bar'.replace(/from:\s*([a-z0-9-]+)/i, function() {
    console.log(arguments);
    return 'from: replaced';
});

If you want to retain the spacing however, you could do the following:

'foo from:2012-01-01 bar'.replace(/from:(\s*)([a-z0-9-]+)/i, function(match, $1) {
    console.log(arguments);
    return 'from:' + $1 + 'replaced';
});

answered Jul 31, 2012 at 21:36

Godwin

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