How do I search a string in Javascript for all instances of [SM_g]randomword[SM_h]. and replace them all with [SM_g]randomword.[SM_h].
I'd also like to do this with commas. For example - I need to be able to turn [SM_g]randomword[SM_h], into [SM_g]randomword,[SM_h].
Here is my code so far:
const periodRegex = /\[SM_g](.*?)\[SM_h](?:[.])/g;
string_afterregex - string_initial.replace(periodRegex, /*I don't know what goes in here*/)
Capture the patterns and then reorder with back reference:
const periodRegex = /(\[SM_g].*?)(\[SM_h])([.,])/g;
var string_initial = '[SM_g]randomword[SM_h].'
var string_afterregex = string_initial.replace(periodRegex, "$1$3$2");
console.log(string_afterregex);
var string_initial = '[SM_g]randomword[SM_h],'
console.log(string_initial.replace(periodRegex, "$1$3$2"))
[SM_g]randomword[SM_h]. into [SM_g]randomword.[SM_h]. instead of [SM_g]randomword.[SM_h] However, I figured out that by changing your regex to /(\[SM_g].*?)(\[SM_h])([.])/g then I would have the solution. If you want to update your solution, I can mark it as correct.
. or , after the randomword instead of simply inserting a character.You don't have to use multiple regexes to achieve what you want if you benefit from lookaheads:
const re = /\[SM_g](?=(((?:(?!\[SM_h]).)*)\[SM_h])([.,]))\1./g;
const str = '[SM_g]$2$3[SM_h]';
console.log("[SM_g]WORD[SM_h], [SM_g]WORD[SM_h]. [SM_g]WORD[SM_h]".replace(re, str));Breakdown:
\[SM_g] Match [SM_g] literally(?= Start of a positive lookahead
( Start of capturing group #1
( Start of CG #2
(?: Start of NCG #1, tempered dot
(?!\[SM_h]). Match next character without skipping over a [SM_h])* End of NCG #1, repeat as much as possible) End of CG #2\[SM_h] Match [SM_h] literally) End of CG #2( Start of CG #3
[.,] Match a comma or a period) End of CG #4) End of positive lookahead\1. Match what's matched by CG #1 then a character