Javascript function is not executed each time when called

Question

I have a javascript function which is called from another function I have.

For some reasons, this function is not executed each time when called. I have tryed to change the name of the function, and then everything works fine.

I don't understand why. Here is a litle example:

javascript 1:

function a()
{ 
   b();
}

javascript 2:

function b()
{ 
   c();
}

javascript 3:

function c()
{ 
   alert("Function c");
}

The function c is not executed for some reasons... If for example the function c will be called newC(), then it works fine.

Are these three different compilation blocks (e.g. files)? What are you actually executing; these are just definitions of functions, how do they get called? — Andrzej Doyle
– Andrzej Doyle, Commented Aug 2, 2012 at 8:08
Could you please provide a running example with proper comments? There is no call to a in your current example. — Zeta
– Zeta, Commented Aug 2, 2012 at 8:12
Thank you for your ansewer @AndrzejDoyle. Function a() is in separate js file and function b() and c() are in the same js file. I am actually executing the first javascript file with the function a(), then that function will call the function b from the second js file and the function b() will call the function c() from the same file. — Milos Cuculovic
– Milos Cuculovic, Commented Aug 2, 2012 at 8:13
@Zeta, thank you for the answer. The function a() is called when a button iz clicked. The function b is executed properly but not the c. — Milos Cuculovic
– Milos Cuculovic, Commented Aug 2, 2012 at 8:15
you said you changed the function names and it worked fine, so please post the original code you wrote with the non-working name. Probably that name was already used by other function... — Carlo Moretti
– Carlo Moretti, Commented Aug 2, 2012 at 8:15

Aaron Digulla · Accepted Answer · 2012-08-02 08:15:26Z

5

You probably have a conflict of names in the scope of b() i.e. when b() is executed, it can happen that c is defined to something else in a current scope.

Solution: Start your JavaScript debugger, set a breakpoint in b() and check what c is at that time.

answered Aug 2, 2012 at 8:15

Aaron Digulla

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1 Comment

Milos Cuculovic Over a year ago

Oh, you're right @Aaron, I have run the debuger and I defined another function with the same name in the js file b, so there was a name conflict. Stupid error from my side. Sorry and thanks again.

Praveen Singh · Accepted Answer · 2012-08-02 08:20:51Z

1

For me it works fine. May be you have some error in the code. IF u post the full code i may able to help. here is the working code

<html>
<head>
<script type="text/javascript">
function a()
{
b();
}
function b()
{
c();
}
function c()
{
alert("hello");
}
</script>
</head>
<body>
<form>
<label>Hello</label>
<button onclick="a()">v</button>
</form>
</body>
</html>

answered Aug 2, 2012 at 8:20

Praveen Singh

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1 Comment

Milos Cuculovic Over a year ago

Thanks, I have found the solution, I defined the function c twice, so there were name conflicts.

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