How to call a function placed in another function with jQuery, without modifying the original code?

Question

This is basically the framework of my code:

var firstfunction = function () {
    function innerfunction () {
        // Do stuff here
    }
}

How do I reference innerfunction(), without changing the code mentioned supra?

What do you mean by "reference [it] by jQuery"? What exactly do you want to do with it? — David G
– David G, Commented Sep 15, 2012 at 0:51
Shouldn't firstfunction.innerfunction() work? Checked and NO - leaving this here for reference. — Eugen Rieck
– Eugen Rieck, Commented Sep 15, 2012 at 0:53

Mark · Accepted Answer · 2012-09-15 00:54:03Z

3

If you want to expose innerFunction as an API you could do the following:

var firstFunction = function () {
  var imPrivate = "foo"
  var innerFunction = function () {
    // do stuff
  }

  return {
    innerFunction : innerFunction
  }
}

firstFunction.innerFunction()

This would also let you create private methods, variables as well.

answered Sep 15, 2012 at 0:54

Mark

5,7302 gold badges28 silver badges26 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

user266647 · Accepted Answer · 2012-09-15 00:53:21Z

0

It seems that you're wanting to make use of currying, this is a functional programming technique where you return an function from another function i.e.:

var f1 = function() {
    return function() {
    }
}

> f1()();

answered Sep 15, 2012 at 0:53

user266647

Collectives™ on Stack Overflow

How to call a function placed in another function with jQuery, without modifying the original code?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related