PHP namespaced class within variable

Question

Can anyone explain why the below code causes a "Cannot find class" error? Instantiating the class with the fully qualified name works, but eliminates the advantage of the "use" statement.

<?php

namespace
{
    use Foo\Bar;

    new Bar;    // Works

    $class = 'Foo\Bar'; 

    new $class; // Works

    $class = 'Bar';

    new $class; // "Cannot find class" error
}

namespace Foo
{
    class Bar {}
}

Thanks

Tested on both PHP 5.3.2 and 5.3.10

kfriend
– kfriend

2012-09-19 16:17:38 +00:00
Commented Sep 19, 2012 at 16:17 — kfriend
– kfriend, Commented Sep 19, 2012 at 16:17

raina77ow · Accepted Answer · 2012-09-19 16:23:03Z

2

Well, I suppose it's actually a feature. And aliases won't help here, for the same reasons:

Importing is performed at compile-time, and so does not affect dynamic class, function or constant names. [...]

<?php 
use My\Full\Classname as Another, My\Full\NSname;

$obj = new Another; // instantiates object of class My\Full\Classname
$a = 'Another'; 
$obj = new $a;      // instantiates object of class Another 
?>

And yes, it sorts of defeats the purpose of use with dynamic classes.

answered Sep 19, 2012 at 16:23

raina77ow

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