Variable classname using namespaces in php

Question

I want to use a variable class name in PHP with a prefixed namespace.

Three variants I have tried produce expectation of an identifier error after the last backslash.

(\api\controllers\(new $class()))->{$method}($this->id);

((new \api\controllers\$class()))->{$method}($this->id);

((new \api\controllers\{$class()}))->{$method}($this->id));

How do I make this work?

What exactly are you trying to accomplish? It seems like you might be jumping through hoops that you could simply walk around instead... — Greg Schmidt
– Greg Schmidt, Commented Apr 15, 2019 at 16:43
If this is a requirement for your application, you should probably rethink the structure of your application. — GrumpyCrouton
– GrumpyCrouton, Commented Apr 15, 2019 at 16:43
I want to pick up the class name in the desired namespace matching other file name in another namespace. I have use command available but I am trying to see if this will work. Please clarify the drawbacks to this approach. Since I use an autoloader I have switched order of autloaded directories which eliminates the class name addressing in this fashion need for this in the present script. — Vahe
– Vahe, Commented Apr 15, 2019 at 16:44
@GregSchmidt, please see stackoverflow.com/questions/55680983/… for context to my application — Vahe
– Vahe, Commented Apr 15, 2019 at 16:51

Greg Schmidt · Accepted Answer · 2019-04-15 16:54:15Z

1

How about this:

$full_class_name = '\api\controllers\' . $class;
$controller = new $full_class_name();
$controller->{$method}($this->id);

It can probably be shortened somewhat, but doing that here would perhaps make the answer more obscure and less helpful.

answered Apr 15, 2019 at 16:54

Greg Schmidt

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1 Comment

Vahe Over a year ago

Thank you, that makes sense, I was overlooking the fact that my $class variable was being added to the end of a literal namespace path. That's why it didn't work.

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