Pull part of string using regExp in perl

Question

Small question regrading taking part of string. my string is

some text here value: 100 .1.3.6 bla bla.

I would like to save the first part of the sting till the .1.3.......

so at the end ill have only

some text here value: 100

JRFerguson · Accepted Answer · 2012-10-10 10:58:16Z

1

$str="some text here value: 100 .1.3.6 bla bla.";$str=~m{^([^.]*)} and print $1'

This matches from the beginning of the string until a dot character appears. The matched portion is captured and printed if there was a match.

answered Oct 10, 2012 at 10:58

JRFerguson

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1 Comment

@user1734552 If this solved your problem, please accept the solution.

Steve · Accepted Answer · 2012-10-10 10:58:23Z

1

This may be what you're looking for (assuming there's only one : per line).

perl -pe 's/(.*: [^ ]+).*/$1/' file.txt

Result:

some text here value: 100

answered Oct 10, 2012 at 10:58

Steve

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