Batch file for parsing command line input that contains comma separated values

Question

I am working on a command line utility that takes set of input parameters as command. Those input parameters are then validated against predefined names. The utility is invoked in this manner:

runUtility.cmd -A -B x,y,z -C w

Here parameters are A, B and C (one that starts with -). Now the validation rules are as follows:

Parameter's name should match predefined names, so that one can not pass any invalid parameter say -UVW
Parameter may or may not have a value. In above example -A has no value, while -B has x,y,z and -C has w.

I have written this code to validate the inputs:

:validate

set argument=%1
set argumentValue=%2


if "%argument%" == "-A" (   
    shift   
    goto validate
)

if "%argument%" == "-B" (
    if "%argumentValue%" == "" (
        echo Empty value for -B
        goto end
    )
    shift
    shift 
    goto validate       
)

if "%argument%" == "-C" (
    if "%argumentValue%" == "" (
        echo Empty value for -C
        goto end
    )
    shift
    shift  
    goto validate      
)

if %argument%" == "" (
        goto end
)

Argument %argument% is invalid

:end

But this does not seem to work, as -B has comma separated values, so for B when it does two shifts, in the next iteration, y becomes %1 and z becomes %2. Since y is not a parameter, it fails with last line of code that "Argument y is invalid". Actually comma is taken as delimiter by SHIFT command, so x,y,z does remain a single value.

I want x,y,z to be taken as a single value OR is there any other way to process this? I am bit new to batch scripting , I tried with FOR loop but there I was not able to get %1 and %2 together in every iteration.

Community · Accepted Answer · 2017-05-23 12:15:07Z

10

Batch uses any combination of space, comma, semicolon, tab, and equal to delimit parameters. If you want to include any of those characters in a parameter, then the parameter must be quoted.

runUtility.cmd -A -B "x,y,z" -C w

Your script can remove the enclosing quotes with the ~ modifier. It is also a good idea to enclose your entire assignment within quotes to guard against problem characters like &, |, etc. The double quotes in the assignment below will not be included in the value.

set "argumentValue=%~2"

I developed an option parser that you might want to look at: Windows Bat file optional argument parsing.

The parsing code hardly changes regardless what options you define. The only things that have to change are the definition of your options using a single variable, the SHIFT /3 should be modified to SHIFT /1, every %~3 becomes %~1, and %~4 becomes %~2.

The option parser has the ability to automatically supply default values for unspecified options.

Assuming you do not have default values, your options would be defined as

set "options=-A: -B:"" -C:"""

Meaning an -A option that does not take a value, and -B and -C options that take values but by default are undefined.

The options are stored in variables that match the option name (dash included).

edited May 23, 2017 at 12:15

CommunityBot

11 silver badge

answered Nov 9, 2012 at 18:38

dbenham

132k29 gold badges272 silver badges410 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

dbenham Over a year ago

EDIT - I corrected the list of changes that must be made to the linked option parser if it is to be used for this question.

Bali C · Accepted Answer · 2012-11-09 17:01:11Z

0

Here is something to get you going, it is based on 3 parameters, A B C, and each having up to 3 parameters separated by a space. It's unfinished as I don't have time to put it all together but it should give you something to work with, which you can tweak as you need.

@echo off
set p1=%1
set p2=%2
set p3=%3
set p4=%4
set params=(-A -B -C)
for %%x in %params% do (
if "%p1%"=="" (
echo No parameters given
exit /b >nul
) else (
if "%p1%"=="%%x" (
if not "%p4%"=="" (
echo %%x has 3 parameters
) else (
if not "%p3%"=="" (
echo %%x has 2 parameters
) else (
if not "%p2%"=="" (
echo %%x has 1 parameter
)
)
)
)
)
)

answered Nov 9, 2012 at 17:01

Bali C

31.4k37 gold badges128 silver badges155 bronze badges

1 Comment

Saurabh Over a year ago

The idea is to validate the parameters for their names and empty values. But when we get comma separated value for any parameter, the code fails. I don't think above solution will work for it. Any suggestion is welcome.

Collectives™ on Stack Overflow

Batch file for parsing command line input that contains comma separated values

2 Answers 2

1 Comment

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related