Using regexes in Ruby

Question

I have a regex, that I'm trying to use in Ruby. Here is my Regex, and it works in Java when I add the double escape keys

\(\*(.*?)\*\)

I know this is a simple question, but how would I write this as a ruby expression and set it equal to a variable? I appreciate any help.

It'd help us check for correctness, if you'd supply some samples of what you expect it to match, and not match. — the Tin Man
– the Tin Man, Commented Nov 13, 2012 at 15:53

operand · Accepted Answer · 2012-11-13 15:46:37Z

2

try this:

myregex = /\(\*(.*?)\*\)/

To be clear, this is just to save the regex to a variable. To use it:

"(**)" =~ myregex

answered Nov 13, 2012 at 15:46

operand

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Comments

Bill Dueber · Accepted Answer · 2012-11-13 15:48:06Z

0

Regular expressions are a native type in Ruby (the actual class is "Pattern"). You can just write:

mypat = /\(\*(.*?)\*\)/

[Looks like anything between '(' / ')' pairs, yes?]

You can then do

m = mypat.match(str)
comment = m[1]

...or, more compactly

comment = mypat.match(str)[1]

answered Nov 13, 2012 at 15:48

Bill Dueber

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1 Comment

Martin Vidner Over a year ago

The actual class, in MRI 1.8 and 1.9, is Regexp.

simonmenke · Accepted Answer · 2012-11-13 15:53:00Z

0

try this:

if /\(\*(.*?)\*\)/ === "(*hello*)"
  content = $1 # => "hello"
end

http://rubular.com/r/7eCuPX3ri0

edited Nov 13, 2012 at 15:53

answered Nov 13, 2012 at 15:43

simonmenke

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2 Comments

operand Over a year ago

I think you mean =~ rather than ==

simonmenke Over a year ago

Ah, it is === or =~ indeed

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