How can I create a (48,64) Numpy array like this:
i, i, i, .....,i
i+0.1, i+0.1,..........,i+0.1
i+0.2, i+0.2,..........,i+0.2
.
.
.
.
i+6.3, i+6.3,..........,i+6.3
0.1 is the fixed difference between rows.
I have solved it perfectly with JoshAdel's answer,
But how about the fixed difference is between columns?i.e.
i,i+0.1,i+0.2.....i+6.3
i,i+0.1,i+0.2.....i+6.3
.
.
.
i,i+0.1,i+0.2.....i+6.3
Thanks a lot!
import numpy as np
i = 10.0
a = np.empty((64,48))
a.fill(i)
a += np.arange(0,6.4,0.1)[:,np.newaxis]
Out[12]:
array([[ 10. , 10. , 10. , ..., 10. , 10. , 10. ],
[ 10.1, 10.1, 10.1, ..., 10.1, 10.1, 10.1],
[ 10.2, 10.2, 10.2, ..., 10.2, 10.2, 10.2],
...,
[ 16.1, 16.1, 16.1, ..., 16.1, 16.1, 16.1],
[ 16.2, 16.2, 16.2, ..., 16.2, 16.2, 16.2],
[ 16.3, 16.3, 16.3, ..., 16.3, 16.3, 16.3]])
A couple of notes:
Numpy's shape convention is (nrow, ncolumn) so you need the shape to be (64,48) not (48,64) to the array that you have in your question.
There are multiple ways to do this, but I chose to use numpy's broadcasting notation.
You can write this more compactly, but I split it into separate steps for illustrative purposes.
