How to extract values from an array of arrays in Javascript?

Question

I have a variable as follows:

var dataset = {
"towns": [
    ["Aladağ", "Adana", [35.4,37.5], [0]],
    ["Ceyhan", "Adana", [35.8,37], [0]],
    ["Feke", "Adana", [35.9,37.8], [0]]
    ]
};

The variable has a lot of town data in it. How can I extract the first elements of the third ones from the data efficiently? I,e, what will ... be below?

var myArray = ...
//myArray == [35.4,35.8,35.9] for the given data

And what to do if I want to store both values in the array? That is

var myArray = ...
//myArray == [[35.4,37.5], [35.8,37], [35.9,37.8]] for the given data

I'm very new to Javascript. I hope there's a way without using for loops.

@Veger Nothing wrong. I'm coming from MATLAB background. That's why I look for non-loop solution I think. — petrichor
– petrichor, Commented Dec 29, 2012 at 16:17
see below, there's a loop free way: stackoverflow.com/questions/14083524/… — bukart
– bukart, Commented Dec 29, 2012 at 16:32

loganfsmyth · Accepted Answer · 2012-12-29 16:16:49Z

8

On newer browsers, you can use map, or forEach which would avoid using a for loop.

var myArray = dataset.towns.map(function(town){
  return town[2];
});
// myArray == [[35.4,37.5], [35.8,37], [35.9,37.8]]

But for loops are more compatible.

var myArray = [];
for(var i = 0, len = dataset.towns.length; i < len; i++){
  myArray.push(dataset.towns[i][2];
}

answered Dec 29, 2012 at 16:16

loganfsmyth

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Comments

Darin Dimitrov · Accepted Answer · 2012-12-29 16:17:00Z

2

Impossible without loops:

var myArray = [];
for (var i = 0; i < dataset.towns.length; i++) {
    myArray.push(dataset.towns[i][2][0]);
}
// at this stage myArray = [35.4, 35.8, 35.9]

And what to do if I want to store both values in the array?

Similar, you just add the entire array, not only the first element:

var myArray = [];
for (var i = 0; i < dataset.towns.length; i++) {
    myArray.push(dataset.towns[i][2]);
}
// at this stage myArray = [[35.4,37.5], [35.8,37], [35.9,37.8]]

answered Dec 29, 2012 at 16:17

Darin Dimitrov

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