display element of array php

Question

I have this PHP/HTML code:

<table>                                                                                        
  <tr>
    <td>Region:</td>
    <td>
      <select style="width:200px" name="region"> 
      <?php for( $i=0;$i<sizeof($regions);$i++) { ?>
      <option value=<?php echo($regions[$i]) ;?>><?php echo( $regions[$i]) ;?></option> 
      <?php }?>
      </select>  
    </td>
</tr>

The problem is the value displayed is ( Array ). I tried to replace echo by printf and sprintf but I have the same result. But if I replaced it with print_r I now have this information (Array ([0] => Alaska[region] => Alaska).

I need to know what I'm doing wrong and how can I fix it?

Marc B · Accepted Answer · 2013-01-04 21:36:57Z

3

If you get Array as your output, then you're actually doing something like:

$x = array();
echo $x;

e.g. you're not outputting an ELEMENT of an array, you're trying to output the entire array.

That means $regions[$i] is itself an array, and you need a sub-index, e.g. $regions[$i][1] instead.

answered Jan 4, 2013 at 21:36

Marc B

362k44 gold badges433 silver badges508 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

lamloumi Over a year ago

thanks i replaced it by $regions[$i][0] and it is work thanks

wonde · Accepted Answer · 2013-01-04 21:43:17Z

0

try this

foreach($regions as $region)
      <option value=<?php echo($region['region']) ;?>><?php echo( $region['region']) ;?></option> 
    <?php }?>

answered Jan 4, 2013 at 21:43

wonde

1,18110 silver badges20 bronze badges

Collectives™ on Stack Overflow

display element of array php

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related